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6a^2+7a^2=0
We add all the numbers together, and all the variables
13a^2=0
a = 13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·13·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{26}=0$
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